By Alfred S. Posamentier
Advanced Euclidean Geometry provides a radical assessment of the necessities of high tuition geometry after which expands these strategies to complicated Euclidean geometry, to offer lecturers extra self belief in guiding pupil explorations and questions.
The textual content includes 1000's of illustrations created within the Geometer's Sketchpad Dynamic Geometry® software program. it really is packaged with a CD-ROM containing over a hundred interactive sketches utilizing Sketchpad™ (assumes that the consumer has entry to the program).
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Additional info for Advanced Euclidean Geometry
This can be written as — 2ra + a " > 0 . Thus > 2ra. Multiplying both sides of this inequality by we get ^ ^----1- a j > r, which is ~(OR + OP) > r, or OM > r. This implies that point M must be outside the circle and that points S and T do not exist. ” I FALLACY 5 ^‘Q r o o f ’ Two segments of unequal length are actually of equal length. Consider AABCy with M N \ \ BC and MN intersecting AB and AC in points M and N, respectively (see Figure 1-^). We will now “prove” that BC = M N . Because MN 11 BC, we have BC AB AAM N ~ AABC a n d -----= ------.
22 ADVANCED EUCLIDEAN GEOMETRY 2. Discover the fallacy in the following “proof”: 45° = 60°. “P r o o f ” Construct equilateral triangle ABC. (See Figure 1-33). On side AB construct isosceles right triangle ADB with AB as hypotenuse. Lay off EB on BC equal in length to BD^ Connect point E to point F, the mid point of ADy and extend to meet AB at point G. Draw GD. Construct perpendicular bisectors of GD and GE. Because GD and ^ GE are not parallel, the per pendicular bisectors must meet at point K.
Sides: a, by c Feet of angle bisectors: T^, Angles: oiy ¡3, y Vertices: A, By C Incenter (point of concurrence of angle bisectors; center of inscribed circle): I Altitudes: h„y hi^y he Inradius (radius of inscribed circle): r Feet of the altitudes: H^, H^,, Circumcenter (point of concurrence of perpendicular bisectors of sides; center of circumscribed circle): O Orthocenter (point of concurrence of altitudes): H Medians: mi,y nic Midpoints of sides: M^, Myy Centroid (point of concurrence of medians): G Angle bisectors: Circumradius (radius of circumscribed circle): R Semiperimeter (half the sum of the lengths of the sides: |(a + i?